Simplify and optimize bit roll operations

Suggested in #1666, ran many testing to check it gives the same results
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altrisi committed 2023-03-08 13:24:37 +01:00
1 parent 3f19cce649
commit 93bec37dac
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@@ -45,10 +45,11 @@ import java.util.List;
import java.util.Map;
import java.util.Set;
import java.util.function.BiFunction;
import java.util.function.BinaryOperator;
import java.util.function.DoubleBinaryOperator;
import java.util.function.DoubleToLongFunction;
import java.util.function.DoubleUnaryOperator;
import java.util.function.Function;
import java.util.function.LongBinaryOperator;
import java.util.function.Supplier;
import java.util.stream.Collectors;
@@ -537,16 +538,16 @@ public class Expression
addUnaryFunction(name, (v) -> new NumericValue(fun.applyAsLong(NumericValue.asNumber(v).getDouble())));
}
public void addMathematicalBinaryIntFunction(String name, BinaryOperator<Long> fun)
public void addMathematicalBinaryIntFunction(String name, LongBinaryOperator fun)
{
addBinaryFunction(name, (w, v) ->
new NumericValue(fun.apply(NumericValue.asNumber(w).getLong(), NumericValue.asNumber(v).getLong())));
new NumericValue(fun.applyAsLong(NumericValue.asNumber(w).getLong(), NumericValue.asNumber(v).getLong())));
}
public void addMathematicalBinaryFunction(String name, BinaryOperator<Double> fun)
public void addMathematicalBinaryFunction(String name, DoubleBinaryOperator fun)
{
addBinaryFunction(name, (w, v) ->
new NumericValue(fun.apply(NumericValue.asNumber(w).getDouble(), NumericValue.asNumber(v).getDouble())));
new NumericValue(fun.applyAsDouble(NumericValue.asNumber(w).getDouble(), NumericValue.asNumber(v).getDouble())));
}