Simplify and optimize bit roll operations
Suggested in #1666, ran many testing to check it gives the same results
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@@ -45,10 +45,11 @@ import java.util.List;
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import java.util.Map;
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import java.util.Set;
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import java.util.function.BiFunction;
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import java.util.function.BinaryOperator;
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import java.util.function.DoubleBinaryOperator;
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import java.util.function.DoubleToLongFunction;
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import java.util.function.DoubleUnaryOperator;
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import java.util.function.Function;
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import java.util.function.LongBinaryOperator;
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import java.util.function.Supplier;
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import java.util.stream.Collectors;
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@@ -537,16 +538,16 @@ public class Expression
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addUnaryFunction(name, (v) -> new NumericValue(fun.applyAsLong(NumericValue.asNumber(v).getDouble())));
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}
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public void addMathematicalBinaryIntFunction(String name, BinaryOperator<Long> fun)
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public void addMathematicalBinaryIntFunction(String name, LongBinaryOperator fun)
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{
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addBinaryFunction(name, (w, v) ->
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new NumericValue(fun.apply(NumericValue.asNumber(w).getLong(), NumericValue.asNumber(v).getLong())));
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new NumericValue(fun.applyAsLong(NumericValue.asNumber(w).getLong(), NumericValue.asNumber(v).getLong())));
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}
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public void addMathematicalBinaryFunction(String name, BinaryOperator<Double> fun)
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public void addMathematicalBinaryFunction(String name, DoubleBinaryOperator fun)
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{
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addBinaryFunction(name, (w, v) ->
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new NumericValue(fun.apply(NumericValue.asNumber(w).getDouble(), NumericValue.asNumber(v).getDouble())));
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new NumericValue(fun.applyAsDouble(NumericValue.asNumber(w).getDouble(), NumericValue.asNumber(v).getDouble())));
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}
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@@ -315,20 +315,8 @@ public class Operators
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expression.addFunctionalEquivalence("<=", "nondecreasing");
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expression.addMathematicalBinaryIntFunction("bitwise_shift_left", (num, amount) -> num << amount);
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expression.addMathematicalBinaryIntFunction("bitwise_shift_right", (num, amount) -> num >> amount);
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expression.addMathematicalBinaryIntFunction("bitwise_roll_left", (num, num2) -> {
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long amount = num2 % 64;
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long amountToRoll = 64 - amount;
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long rolledBits = ((-1L) >> amountToRoll) << amountToRoll;
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long rolledAmount = (num & rolledBits) >> amountToRoll;
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return num << amount | rolledAmount;
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});
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expression.addMathematicalBinaryIntFunction("bitwise_roll_right", (num, num2) -> {
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long amount = num2 % 64;
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long amountToRoll = 64 - amount;
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long rolledBits = ((-1L) << amountToRoll) >> amountToRoll;
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long rolledAmount = (num & rolledBits) << amountToRoll;
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return num >> amount | rolledAmount;
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});
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expression.addMathematicalBinaryIntFunction("bitwise_roll_left", (num, amount) -> Long.rotateLeft(num, (int)amount));
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expression.addMathematicalBinaryIntFunction("bitwise_roll_right", (num, amount) -> Long.rotateRight(num, (int)amount));
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expression.addMathematicalUnaryIntFunction("bitwise_not", d -> {
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long num = (long) d;
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return ~num;
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